25x-2x^2=63

Solution for 25x-2x^2=63 equation:

25x-2x^2=63

We move all terms to the left:

25x-2x^2-(63)=0

a = -2; b = 25; c = -63;
Δ = b2-4ac
Δ = 252-4·(-2)·(-63)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-11}{2*-2}=\frac{-36}{-4}
=+9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+11}{2*-2}=\frac{-14}{-4}
=3+1/2
$